SÉRIES TRANSCENDENTES DE ANCELMO L. GRACELI

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ / [Gn]

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ / / [ ${{\ln(n!)} \over n}$ ] / [Gn]

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ / / $\Gamma (z)$ / [Gn]

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ $n \choose k$ / / [ ${{\ln(n!)} \over n}$ ] / [Gn]

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ / / [ $E_{n}$ ] / $\Gamma (z)$ / [Gn]

[-] [Gn]

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ / / [ $E_{n}$ ] / $\Gamma (z)$ / [Gn]

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ / / [ $E_{n}$ ] / $\Gamma (z)$ / [Gn] = $\sum _{n=1}^{\infty }a_{n}$ [Gn] =

[-] [Gn]

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ / / $\Gamma (z)$ / [Gn]

[-] [Gn]

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ / / [ $E_{n}$ ] / $\Gamma (z)$ / [Gn]

[-] [Gn]

f [x] = $\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ / $n \choose k$ / [ $E_{n}$ ] / $\Gamma (z)$ / [Gn]

$S=\sum _{}^{}u_{n}$ . $\exp(x)$ $n \choose k$ $\Gamma (z)$ - /[Gn]