SÉRIES TRANSCENDENTES DE ANCELMO L. GRACELI

CÁLCULO SINTÉTICO DE ANCELMO L. GRACELI, COM NÚMERO DE GRACELI [Gn].

[Gn] = NÚMERO TRANSCENDENTE DE ANCELMO L. GRACELI.

PI [Π] / 1.1 = 3.141591 / 1.1 = 2.855992727 = [Gn]

1 / PG3 = PROGRESSÃO GEOMéTRICA E SEQUENCIAL DE 3. = [Gn]

1 / 3 = 0.33333333333333333

1 / 9 = 0.111111111

1 / 27 =0.037037037037

1 / 81= 0.0123456789

1/ 243 = 0.00411522633

1 / 729 = 0.00411522633

$\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ $n \choose k$ / [ ${{\ln(n!)} \over n}$ ] / [[Gn]] / [Gn]

$S=\sum _{}^{}u_{n}$ . $\exp(x)$ $n \choose k$ / [ ${{\ln(n!)} \over n}$ ] / [[Gn]] /[Gn]

$\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ $n \choose k$ / [ ${{\ln(n!)} \over n}$ ] / [[Gn]] / $\Gamma (z)$ /[Gn]

$S=\sum _{}^{}u_{n}$ . $\exp(x)$ $n \choose k$ / [ ${{\ln(n!)} \over n}$ ] / [[Gn]] / $\Gamma (z)$ / [Gn]

$\sum _{n=1}^{\infty }a_{n}$ / [Gn] / $\exp(x)$ $n \choose k$ / [ ${{\ln(n!)} \over n}$ ] / [ $E_{n}$ ] / $\Gamma (z)$ / [ [Gn]]=

$S=\sum _{}^{}u_{n}$ . / [Gn] / $\exp(x)$ $n \choose k$ / [ ${{\ln(n!)} \over n}$ ] / [ $E_{n}$ ] / $\Gamma (z)$ / [ [Gn]]=

$\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ $n \choose k$ / / [Gn]

$S=\sum _{}^{}u_{n}$ $\exp(x)$ $n \choose k$ . / [Gn]

$\sum _{n=1}^{\infty }a_{n}$ $\exp(x)$ $\Gamma (z)$ - /[Gn]

$S=\sum _{}^{}u_{n}$ . $\exp(x)$ $\Gamma (z)$ - /[Gn]